c^2+80=18c

Solution for c^2+80=18c equation:

c^2+80=18c

We move all terms to the left:

c^2+80-(18c)=0

a = 1; b = -18; c = +80;
Δ = b2-4ac
Δ = -182-4·1·80
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2}{2*1}=\frac{16}{2}
=8
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2}{2*1}=\frac{20}{2}
=10
$